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Post by James Hennigan

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The distribution of mass is always relevant to rotational motion. I assume the formula you are thinking of is T=2πsqrt(L/g)
This only holds for 'simple' pendulums: Pendulums which consist of a bob hanging from a massless thread.

In general, a pendulum can be a rigid object. The more general equation for the period at low amplitudes is T=2πsqrt(I/Mgh); where I is the moment of inertia of the body, M is its mass, and h is the distance from the pivot to the center of mass of the body.
Both I and h depend on how the mass is distributed.

Also, the formulas in my previous post should be valid even for the very small angles involved in head balancing.

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by James Hennigan, in response to this post 2016-03-31 21:52:08


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